n

lim(n→+∞)⁡ ∑ (3/4)^k =
k=1

the n is supposed to be above the sigma sign and the k=1 is supposed to be below the sigma sign. thanks.

2 answers

http://en.wikipedia.org/wiki/Geometric_series#Sum

sum=3/4 * 1/(3/4)= 3/4*4/3=1

check that.
could you also tell me what the series will be ?
thanks.