Question

n engineer runs a test to locate errors in his software. The test scans each line of code in the software. The proportional relationship between the lines scanned and the errors found is shown in the table.
Lines Scanned Errors Found
59
1

l
5

1,180
20

1,770
30

Which statement describes how to solve for l,
the unknown value in the table?

Select the answer that is completely correct.

Responses

The relationship between lines scanned and errors found can be represented by the equation e=159l.
Since l
lines correspond with 5
errors, substitute 5
for e
and solve. The unknown value, l,
is 295.
The relationship between lines scanned and errors found can be represented by the equation Since l lines correspond with 5 errors, substitute 5 for e and solve. The unknown value, l textsf comma is

The relationship between lines scanned and errors found can be represented by the equation e=159l.
Since l
lines correspond with 5
errors, substitute 5
for e
and solve. The unknown value, l,
is 118.
The relationship between lines scanned and errors found can be represented by the equation Since l lines correspond with 5 errors, substitute 5 for e and solve. The unknown value, l textsf comma is

The relationship between lines scanned and errors found can be represented by the equation e=559l.
Since l
lines correspond with 5
errors, substitute 5
for e
and solve. The unknown value, l,
is 118.

Answer 1

To find the relationship between lines scanned (l) and errors found (e), we should first determine the proportional relationship from the values given in the table. We notice that as the number of lines scanned increases, the number of errors found increases proportionally.

From the table:
- For 59 lines scanned, there is 1 error found.
- For 1,180 lines scanned, there are 20 errors found.
- For 1,770 lines scanned, there are 30 errors found.

First, we can find the "errors per line" ratio based on the values already provided.

1. For 59 lines and 1 error:
\[
\text{Error Rate} = \frac{1}{59}
\]

2. For 1,180 lines and 20 errors:
\[
\text{Error Rate} = \frac{20}{1180} = \frac{1}{59}
\]

3. For 1,770 lines and 30 errors:
\[
\text{Error Rate} = \frac{30}{1770} = \frac{1}{59}
\]

This consistent error rate suggests the relationship \( e = \frac{1}{59}l \) or equivalently \( e = \frac{l}{59} \).

Now, solving for the unknown \( l \) when given \( e = 5 \):
\[
5 = \frac{l}{59}
\]
Multiplying both sides by 59 gives:
\[
l = 5 \times 59 = 295
\]

Based on this reasoning, the statement that accurately describes the solution would be:

**The relationship between lines scanned and errors found can be represented by the equation \( e = \frac{1}{59}l \). Since \( l \) lines correspond with 5 errors, substitute 5 for \( e \) and solve. The unknown value, \( l \), is 295.**