(A) To write a linear equation that expresses the temperature T in terms of altitude A in thousands of feet, we can use the given condition that the temperature drops about 3.6F for each 1,000-foot rise in altitude.
Let's assume that at sea level (A = 0), the temperature is T = 65F. As the altitude increases by 1,000 feet (A = 1), the temperature drops by 3.6F.
Therefore, the equation that expresses the temperature in terms of altitude is:
T = 65 - 3.6A
(B) To find the altitude at which the temperature is 11F, we can substitute T = 11 into the equation we obtained in part (A) and solve for A.
11 = 65 - 3.6A
Rearranging the equation, we get:
3.6A = 65 - 11
3.6A = 54
Dividing both sides by 3.6, we have:
A = 54/3.6
A = 15
Therefore, the altitude at which the temperature is 11F is 15,000 feet.
n certain conditions, the air temperature drops about 3.6F for each 1,000-foot rise in altitude.
(A) If the temperature at sea level is 65F, write a linear equation that expresses the temperature T in terms of altitude A in thousands of feet.
(B) At what altitude is the temperature 11
F?
1 answer