Formula:
CI95 = mean + or - 1.96(sd/√n)
Substituting your data:
CI95 = 41.6 + or - 1.96(7.5/√24)
Finish the calculations for your confidence interval.
n a hospital 24 operating rooms were sampled. The mean noise level was 41.6 decibels and the standard deviation was 7.5. What is the 95% confidence interval of the true mean of the noise levels in the operating rooms? If possible, can you list the steps you used. I'm having a hard time calculating these results. Thanks.
2 answers
Thank you very much for the clarification.
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