I'm not sure of your information. Does that mean a mean of 0 and a standard deviation of 7.6? If so:
Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
N(0,7.6) Find the proportion of observations that are between -10 and 10.
please show your steps
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