To find the minimum number of orange and green forms that Myra could print such that the number of each type is the same, we will start by determining how many forms fit on one page and then find the least common multiple (LCM) of the numbers of forms that fit on a page.
We know:
- 4 orange forms fit on a page, meaning that Myra can print multiples of \(4\) orange forms.
- 8 green forms fit on a page, meaning that Myra can print multiples of \(8\) green forms.
Let \(x\) be the number of orange forms and \(y\) be the number of green forms. We are looking for the smallest integer \(n\) such that:
\[ x = n \cdot 4 \] \[ y = n \cdot 8 \]
To determine \(x\) and \(y\) such that \(x = y\), we need to set \(n \cdot 4\) equal to \(n \cdot 8\):
\[ n \cdot 4 = n \cdot 8 \]
This equality will not hold for any positive integer \(n\) except when we find common multiples rather than setting them equal in that way. Instead, we should find the smallest number \(k\) such that:
\[ k \text{ (number of orange forms)} = k \text{ (number of green forms)} \]
This leads to finding the least common multiple (LCM) of \(4\) and \(8\):
- The multiples of \(4\) are \(4, 8, 12, 16, 20, ...\)
- The multiples of \(8\) are \(8, 16, 24, ...\)
The smallest common multiple is:
\[ \text{LCM}(4, 8) = 8 \]
From this, we realize that Myra needs to print a total of \(8\) forms of both colors:
- To achieve \(8\) orange forms, she needs to print:
\[ \frac{8}{4} = 2 \text{ pages} \quad \text{(because 4 forms fit on 1 page)} \]
- To achieve \(8\) green forms, she needs to print:
\[ \frac{8}{8} = 1 \text{ page} \quad \text{(because 8 forms fit on 1 page)} \]
Thus, the minimum number of each form Myra could print, while ensuring she has equal numbers of orange and green forms, is:
\[ \boxed{8} \]
This means she will print exactly \(8\) orange forms and \(8\) green forms.