My question is, “ A line with slope 3/2 that passes through the point (-2,0)” I have to find an equation. Can someone give me a rough explanation of how to do this, so i can figure this out? Thanks!

Answer 1

y = m x + b
is a straight line that has slope m and when x = 0, y = b
now we already know m = 3/2
so
y = (3/2) x + b
and we have y = 0 when x = -2
so
0 = (3/2)(-2) + b
0 = -3 + b
b = 3
so
y = (3/2) x + 3
or
2 y = 3 x + 6

Answer 2

THANK YOU!!!!!!!

Answer 3

You are welcome.

Answer 4

use the point-slope form of a line. The line with slope m that passes through (h,k) is

y-k = m(x-h)
So, using your numbers,
y-0 = 3/2 (x+2)

you can massage that as you will