Let's make this a little simpler. Why not call a1 just a. Then
4a + 3O2 ==> 2A2O3. On second thought, I'll bet that is Al (for aluminum so that's an ell and not a number 1) so
4Al + 3O2 ==> 2Al2O3.
What I do for limiting regent(LR) problems is to convert Al to mols Al2O3. Do the same with O2 to mols Al2O3. The one producing the smaller number of mols for Al2O3 is the LR.
0.32 mols Al x (2 mols Al2O3/4 mols Al) = 0.32 x 2/4 = ?
0.26 mols O2 x (2 mols Al2O3/3 mols O2) = 0.26 x 2/3 = ?
The reagent that produces the smaller number of mols Al2O3 is the LR.
I don't know what 0.228 missing means for your answer.
My question: 4a1+302--2A1203
Which reactant is limiting if 0.32 mol A1and 0.26mol oxygen is available.
My answer is 0.228 is missing
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