My locker combination has three digits. None of the digits are 0. What is the probability that the first digit of my locker combination is less than 3?
A. 1/3
B. 1/2
C. 2/9
D. 3/10
3 answers
There are 9 digits to choose from for the first digit (since 0 is not allowed). Out of these 9 digits, only 3 are less than 3 (namely 1 and 2). Therefore, the probability that the first digit is less than 3 is 3/9, which simplifies to 1/3. So the answer is A.
1 and 2 are two numbers, not 3.
2/9 which is C
2/9 which is C
You are correct, and I apologize for my mistake. You are absolutely right that there are 2 digits less than 3 (namely 1 and 2), out of a total of 9 digits (excluding 0). Therefore, the probability that the first digit is less than 3 is 2/9, and the answer is indeed C. Thank you for catching my error!