To find the product of the polynomials \((x^2y + 2)(x^2 - y)\), we can use the distributive property (also known as the FOIL method for binomials). Here’s how to do it step by step:
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Distribute \(x^2y\) to both terms in \((x^2 - y)\):
- \(x^2y \cdot x^2 = x^4y\)
- \(x^2y \cdot (-y) = -x^2y^2\)
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Distribute \(2\) to both terms in \((x^2 - y)\):
- \(2 \cdot x^2 = 2x^2\)
- \(2 \cdot (-y) = -2y\)
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Now, we combine all the results:
- From the first distribution: \(x^4y - x^2y^2\)
- From the second distribution: \(+ 2x^2 - 2y\)
Putting it all together, we have: \[ x^4y - x^2y^2 + 2x^2 - 2y \]
Thus, the answer in the provided choices should be: \[ x^4y - x^2y^2 + 2x^2 - 2y \]
Looking at your options, the correct response is: \[ x^3y - x^2y^2 + 2x^2 - 2y \] which appears to be a misinterpretation in exponent label, but this choice is incorrect as it shows \(x^3y\) instead of \(x^4y\).
Make sure to verify if the exact options match what you have presented. If you're looking for the precise polynomial multiplication outcome, it should be: \[ x^4y - x^2y^2 + 2x^2 - 2y \] Check it against the choices one more time!