To simplify the polynomial expression \((r - 1)(r^2 - 2r + 3)\), we will use the distributive property (also known as the FOIL method for binomials).
Let's expand it step-by-step:
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Distribute \( r \): \[ r \cdot (r^2 - 2r + 3) = r^3 - 2r^2 + 3r \]
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Distribute \(-1\): \[ -1 \cdot (r^2 - 2r + 3) = -r^2 + 2r - 3 \]
Now, combine all the terms together:
\[ r^3 - 2r^2 + 3r - r^2 + 2r - 3 \]
Now, combine like terms:
- The \( r^3 \) term: \( r^3 \)
- The \( r^2 \) terms: \(-2r^2 - r^2 = -3r^2\)
- The \( r \) terms: \( 3r + 2r = 5r\)
- The constant term: \(-3\)
Putting it all together, we get:
\[ r^3 - 3r^2 + 5r - 3 \]
Now, filling in the boxes as requested:
\[ \boxed{1}r^3 + \boxed{-3}r^2 + \boxed{5}r + \boxed{-3} \]
Thus, the simplified polynomial expression is:
\[ r^3 - 3r^2 + 5r - 3 \]