Asked by pookie
                Multiply the polynomials (3xβ1)(2x+4)
(
3
π₯
β
1
)
(
2
π₯
+
4
)
.(2 points)
x2+
π₯
2
+
x+
π₯
+
            
        (
3
π₯
β
1
)
(
2
π₯
+
4
)
.(2 points)
x2+
π₯
2
+
x+
π₯
+
Answers
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                    Answered by
            GPT-4o mini
            
    To multiply the polynomials \((3x - 1)(2x + 4)\), we can use the distributive property (often referred to as the FOIL method for binomials).
Let's distribute each term in the first polynomial to each term in the second polynomial:
1. Multiply \(3x\) by \(2x\):
\[
3x \cdot 2x = 6x^2
\]
2. Multiply \(3x\) by \(4\):
\[
3x \cdot 4 = 12x
\]
3. Multiply \(-1\) by \(2x\):
\[
-1 \cdot 2x = -2x
\]
4. Multiply \(-1\) by \(4\):
\[
-1 \cdot 4 = -4
\]
Now we combine all the results:
\[
6x^2 + 12x - 2x - 4
\]
Combine like terms (the \(12x\) and \(-2x\)):
\[
6x^2 + (12x - 2x) - 4 = 6x^2 + 10x - 4
\]
So, the product of the polynomials \((3x - 1)(2x + 4)\) is:
\[
\boxed{6x^2 + 10x - 4}
\]
    
Let's distribute each term in the first polynomial to each term in the second polynomial:
1. Multiply \(3x\) by \(2x\):
\[
3x \cdot 2x = 6x^2
\]
2. Multiply \(3x\) by \(4\):
\[
3x \cdot 4 = 12x
\]
3. Multiply \(-1\) by \(2x\):
\[
-1 \cdot 2x = -2x
\]
4. Multiply \(-1\) by \(4\):
\[
-1 \cdot 4 = -4
\]
Now we combine all the results:
\[
6x^2 + 12x - 2x - 4
\]
Combine like terms (the \(12x\) and \(-2x\)):
\[
6x^2 + (12x - 2x) - 4 = 6x^2 + 10x - 4
\]
So, the product of the polynomials \((3x - 1)(2x + 4)\) is:
\[
\boxed{6x^2 + 10x - 4}
\]
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