To multiply the given polynomials \( (2x - 7)(3x^2 + 7x - 8) \), we can use the distributive property (also known as the FOIL method for binomials):
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Multiply \( 2x \) by each term in the second polynomial: \[ 2x \cdot 3x^2 = 6x^3 \] \[ 2x \cdot 7x = 14x^2 \] \[ 2x \cdot (-8) = -16x \]
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Multiply \( -7 \) by each term in the second polynomial: \[ -7 \cdot 3x^2 = -21x^2 \] \[ -7 \cdot 7x = -49x \] \[ -7 \cdot (-8) = 56 \]
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Now, combine all the results: \[ 6x^3 + (14x^2 - 21x^2) + (-16x - 49x) + 56 \]
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Combine like terms: \[ 6x^3 + (-7x^2) + (-65x) + 56 \]
So, the resulting polynomial in descending order is: \[ 6x^3 - 7x^2 - 65x + 56 \]
Now we can identify the coefficients for each term:
- The coefficient of \( x^3 \) is 6.
- The coefficient of \( x^2 \) is -7.
- The coefficient of \( x \) is -65.
- The coefficient of the constant is 56.
Final Answers
- The value of the coefficient of the \( x^3 \) is 6.
- The value of the coefficient of the \( x^2 \) is -7.
- The value of the coefficient of the \( x \) is -65.
- The value of the coefficient of the constant is 56.