To multiply the conjugates (3/5 - q)(3/5 + q), we can apply the difference of squares formula.
The difference of squares formula states that (a - b)(a + b) = a^2 - b^2.
In this case, a = 3/5 and b = q. Thus, applying the difference of squares formula, we have:
(3/5 - q)(3/5 + q) = (3/5)^2 - q^2
= 9/25 - q^2
multiply the conjugates
(3/5-q)(3/5+q)
3 answers
square the binomial
(w+7^2)
(w+7^2)
To square the binomial (w + 7^2), we need to apply the formula for squaring a binomial.
The formula for squaring a binomial (a + b) is (a + b)^2 = a^2 + 2ab + b^2.
In this case, a = w and b = 7^2 = 49. Therefore, using the formula, we have:
(w + 7^2)^2 = (w)^2 + 2(w)(7^2) + (7^2)^2
= w^2 + 2w(49) + 49^2
= w^2 + 98w + 2401
So, the square of the binomial (w + 7^2) is w^2 + 98w + 2401.
The formula for squaring a binomial (a + b) is (a + b)^2 = a^2 + 2ab + b^2.
In this case, a = w and b = 7^2 = 49. Therefore, using the formula, we have:
(w + 7^2)^2 = (w)^2 + 2(w)(7^2) + (7^2)^2
= w^2 + 2w(49) + 49^2
= w^2 + 98w + 2401
So, the square of the binomial (w + 7^2) is w^2 + 98w + 2401.