Multiply linear expressions quick check apply the disruptive property to multiply 3a3b2 ( 6ab + 7A to be

Answer 1

To multiply the expressions 3a^3b^2 and 6ab + 7a, we need to apply the distributive property.

First, we distribute 3a^3b^2 to each term in 6ab + 7a:

3a^3b^2 * 6ab = 18a^4b^3

3a^3b^2 * 7a = 21a^4b^2

Next, we combine the terms:

18a^4b^3 + 21a^4b^2

Therefore, the product of 3a^3b^2 and 6ab + 7a is 18a^4b^3 + 21a^4b^2.