factor the numberator:
(k+3)(3k+2)(4k-2)
which leaves after the deominator divides out, your answer.
Multiply. (k+3)/(4k-2)*(12k^2+2k-4)
a. 3(k+3)/3k+2
b. 3(k+3)(2k-1)/2
c. (k+3)(3k+2)***
d. (3k+1)(2k+3)
Please help? Thanks
1 answer