Multiply. Give your answer in standard form.

Question

(2n2+5n+4)(2n−4)

Show your work

Answer 1

First we need to distribute the terms in the second set of parentheses to each term in the first set of parentheses:

2n2(2n) + 2n2(-4) + 5n(2n) + 5n(-4) + 4(2n) + 4(-4)

Now multiply each set of terms:

4n^3 - 8n^2 + 10n^2 - 20n + 8n - 16

Combining like terms, we get:

4n^3 + 2n^2 - 12n - 16

Therefore, the answer in standard form is:

4n^3 + 2n^2 - 12n - 16