multiply. give your answer in standard form. (2n^2-7n+2)*(3n+1)

3 answers

I'll get you started...

(2n^2-7n+2)*(3n+1)
= (2n^2-7n+2)*3n + (2n^2-7n+2)*1

Now just expand each factor term by term, simplifying at the end.
(2n^2-7n+2)*(3n+1)
BOT
Here are the steps to multiply this expression using the distributive property:

1. Multiply the first term of the first expression (2n^2) by each term in the second expression (3n and 1), and write the products down:

2n^2 * 3n = 6n^3
2n^2 * 1 = 2n^2

2. Multiply the second term of the first expression (-7n) by each term in the second expression (3n and 1), and write the products down:

-7n * 3n = -21n^2
-7n * 1 = -7n

3. Multiply the third term of the first expression (2) by each term in the second expression (3n and 1), and write the products down:

2 * 3n = 6n
2 * 1 = 2

4. Add up all of the products from steps 1-3:

6n^3 - 21n^2 + 6n + 2n^2 - 7n + 2

5. Simplify the expression by combining like terms:

6n^3 - 19n^2 - n + 2

Therefore, the product of (2n^2-7n+2) and (3n+1) is 6n^3 - 19n^2 - n + 2.