Multiply.
-7v^3*5v
11 answers
-35v^4
Find the area of a circle with diameter 8in.
Use the value 3.14 for π, and do not round your answer.
Use the value 3.14 for π, and do not round your answer.
The formula for the area of a circle is A = πr^2, where r is the radius of the circle. In this case, the diameter is given as 8 inches, so the radius is half of that, which is 4 inches.
Now, substitute the value of the radius into the formula:
A = 3.14 * (4 inches)^2
Simplifying:
A = 3.14 * 16 square inches
A = 50.24 square inches
Therefore, the area of the circle is 50.24 square inches.
Now, substitute the value of the radius into the formula:
A = 3.14 * (4 inches)^2
Simplifying:
A = 3.14 * 16 square inches
A = 50.24 square inches
Therefore, the area of the circle is 50.24 square inches.
Simplify.
w^3*w^5*w
w^3*w^5*w
To simplify this expression, we can combine the exponents by adding them together.
w^3 * w^5 * w = w^(3+5+1) = w^9
So, the simplified form of the expression is w^9.
w^3 * w^5 * w = w^(3+5+1) = w^9
So, the simplified form of the expression is w^9.
a solution to 6x-7y=-19.
To find a solution to the equation 6x - 7y = -19, we need to assign values to either x or y and solve for the other variable. Let's solve for x by assigning a value to y.
Let's say y = 0.
Substituting y = 0 in the equation, we get:
6x - 7(0) = -19
6x = -19
x = -19/6
Therefore, one solution to the equation is x = -19/6 when y = 0.
Let's say y = 0.
Substituting y = 0 in the equation, we get:
6x - 7(0) = -19
6x = -19
x = -19/6
Therefore, one solution to the equation is x = -19/6 when y = 0.
Keiko tutors history. For each hour that she tutors, she earns 20 dollars.
Let A be the amount Keiko earns (in dollars) after tutoring for H hours.
Write an equation relating A to H. Then use this equation to find how much Keiko earns after tutoring for 13 hours.
Let A be the amount Keiko earns (in dollars) after tutoring for H hours.
Write an equation relating A to H. Then use this equation to find how much Keiko earns after tutoring for 13 hours.
The equation relating A (amount earned) to H (hours tutored) is given by A = 20H, since for each hour she tutors, she earns 20 dollars.
To find how much Keiko earns after tutoring for 13 hours, we substitute H = 13 into the equation:
A = 20(13)
A = 260
Therefore, Keiko earns 260 dollars after tutoring for 13 hours.
To find how much Keiko earns after tutoring for 13 hours, we substitute H = 13 into the equation:
A = 20(13)
A = 260
Therefore, Keiko earns 260 dollars after tutoring for 13 hours.
Solve the system of equations.
y=2x+48
y=8x
y=2x+48
y=8x
To solve the system of equations:
y = 2x + 48
y = 8x
We can set the right sides of the equations equal to each other:
2x + 48 = 8x
Simplifying:
48 = 6x
Dividing both sides by 6:
8 = x
Now, substitute x = 8 back into one of the original equations to solve for y:
y = 8(8)
y = 64
The solution to the system of equations is x = 8 and y = 64.
y = 2x + 48
y = 8x
We can set the right sides of the equations equal to each other:
2x + 48 = 8x
Simplifying:
48 = 6x
Dividing both sides by 6:
8 = x
Now, substitute x = 8 back into one of the original equations to solve for y:
y = 8(8)
y = 64
The solution to the system of equations is x = 8 and y = 64.