Asked by S
Multiply (6x - 5y) (-3x + 2y)
Answers
Answered by
GPT-4o mini
To multiply the expressions \((6x - 5y)\) and \((-3x + 2y)\), we will use the distributive property (also known as the FOIL method for binomials):
\[
(6x - 5y)(-3x + 2y)
\]
We will multiply each term in the first expression by each term in the second expression:
1. **First terms**:
\[
6x \cdot (-3x) = -18x^2
\]
2. **Outer terms**:
\[
6x \cdot 2y = 12xy
\]
3. **Inner terms**:
\[
-5y \cdot (-3x) = 15xy
\]
4. **Last terms**:
\[
-5y \cdot 2y = -10y^2
\]
Now, combine all these results together:
\[
-18x^2 + 12xy + 15xy - 10y^2
\]
Next, we can combine the like terms (\(12xy\) and \(15xy\)):
\[
-18x^2 + (12xy + 15xy) - 10y^2 = -18x^2 + 27xy - 10y^2
\]
Thus, the final result is:
\[
\boxed{-18x^2 + 27xy - 10y^2}
\]
\[
(6x - 5y)(-3x + 2y)
\]
We will multiply each term in the first expression by each term in the second expression:
1. **First terms**:
\[
6x \cdot (-3x) = -18x^2
\]
2. **Outer terms**:
\[
6x \cdot 2y = 12xy
\]
3. **Inner terms**:
\[
-5y \cdot (-3x) = 15xy
\]
4. **Last terms**:
\[
-5y \cdot 2y = -10y^2
\]
Now, combine all these results together:
\[
-18x^2 + 12xy + 15xy - 10y^2
\]
Next, we can combine the like terms (\(12xy\) and \(15xy\)):
\[
-18x^2 + (12xy + 15xy) - 10y^2 = -18x^2 + 27xy - 10y^2
\]
Thus, the final result is:
\[
\boxed{-18x^2 + 27xy - 10y^2}
\]
There are no human answers yet. A form for humans to post answers is coming very soon!