multiply (3a + 2c)(9a² - 6ac + 4c²)

Answer 1

To multiply the expressions (3a + 2c)(9a² - 6ac + 4c²), we can use the distributive property and multiply each term in the first expression by each term in the second expression.

First, we multiply the first term in the first expression by each term in the second expression:

(3a) * (9a² - 6ac + 4c²) = 27a³ - 18a²c + 12ac²

Next, we multiply the second term in the first expression by each term in the second expression:

(2c) * (9a² - 6ac + 4c²) = 18ac² - 12ac² + 8c³

Combining the results, we have:

27a³ - 18a²c + 12ac² + 18ac² - 12ac² + 8c³

Simplifying further:

27a³ + 8c³