Did some rethinking..is it
128x^16y^8
?
multiply:
(2x^4y^2)^3 (4x^2y)^2
Is this right?
128x^11y^8
Not sure.
3 answers
I got 128x^16y^8
Great...i was adding the exponents that were on the outside instead of multiplying it.
Took me a while to remember the rule. Thanks Ron.
Took me a while to remember the rule. Thanks Ron.