Multiple Choice
Solve for x.
4(x – b) = x
(1 point)
Responses
b = 4 over 3x
b = Image with alt text: 4 over 3 x
b = three fourthsx
b = Image with alt text: three fourths x
x =4 over 3b
x = Image with alt text: 4 over 3 b
x = three fourthsb
7 answers
x = 4 over 3b
Solve for y, then find the value of y when given x = –2.
6x = 7 – 4y
(1 point)
Responses
–12
–12
7 over 4
Image with alt text: 7 over 4
19 over 4
Image with alt text: 19 over 4
24
6x = 7 – 4y
(1 point)
Responses
–12
–12
7 over 4
Image with alt text: 7 over 4
19 over 4
Image with alt text: 19 over 4
24
To solve for y, we can start by isolating the y term on one side of the equation:
6x = 7 - 4y
First, we will move the constant term (7) to the other side by subtracting it from both sides:
6x - 7 = -4y
Next, we can divide both sides of the equation by -4 to solve for y:
y = (6x - 7) / -4
To find the value of y when x = -2, we substitute -2 for x in the equation:
y = (6(-2) - 7) / -4
y = (-12 - 7) / -4
y = -19 / -4
y = 19/4
Therefore, the correct option is:
y = 19 over 4
6x = 7 - 4y
First, we will move the constant term (7) to the other side by subtracting it from both sides:
6x - 7 = -4y
Next, we can divide both sides of the equation by -4 to solve for y:
y = (6x - 7) / -4
To find the value of y when x = -2, we substitute -2 for x in the equation:
y = (6(-2) - 7) / -4
y = (-12 - 7) / -4
y = -19 / -4
y = 19/4
Therefore, the correct option is:
y = 19 over 4
Solve for h.
A = one-halfbh
(1 point)
Responses
h= The fraction is 2A over b.
h= Image with alt text: The fraction is 2A over b.
2A =
2 A = Image with alt text:
h = one-halfAb
h = Image with alt text: one-half Ab
h = 2Ab
A = one-halfbh
(1 point)
Responses
h= The fraction is 2A over b.
h= Image with alt text: The fraction is 2A over b.
2A =
2 A = Image with alt text:
h = one-halfAb
h = Image with alt text: one-half Ab
h = 2Ab
To solve for h in the equation A = one-halfbh, we can start by isolating h on one side of the equation.
First, we will multiply both sides by 2 to get rid of the fraction:
2A = bh
Next, we want to isolate h by dividing both sides of the equation by b:
h = 2A / b
Therefore, the correct option is:
h = The fraction is 2A over b.
First, we will multiply both sides by 2 to get rid of the fraction:
2A = bh
Next, we want to isolate h by dividing both sides of the equation by b:
h = 2A / b
Therefore, the correct option is:
h = The fraction is 2A over b.
Find the width of a rectangle with a perimeter of 90 and a length of 15. Draw and label the rectangle first to set up your problem.
(1 point)
Responses
90
90
15
15
45
45
30
(1 point)
Responses
90
90
15
15
45
45
30
To find the width of a rectangle, we need to use the formula for the perimeter of a rectangle:
Perimeter = 2 * (length + width)
Given that the length is 15 and the perimeter is 90, we can substitute these values into the formula:
90 = 2 * (15 + width)
To isolate the width, we need to solve for it. We can start by dividing both sides of the equation by 2:
45 = 15 + width
Next, we can isolate the width by subtracting 15 from both sides:
30 = width
Therefore, the width of the rectangle is 30.
Perimeter = 2 * (length + width)
Given that the length is 15 and the perimeter is 90, we can substitute these values into the formula:
90 = 2 * (15 + width)
To isolate the width, we need to solve for it. We can start by dividing both sides of the equation by 2:
45 = 15 + width
Next, we can isolate the width by subtracting 15 from both sides:
30 = width
Therefore, the width of the rectangle is 30.
1 answer