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Multiple Choice Question

Molly's family has $3,000 set aside for an upcoming vacation. The family plans to spend
3/5
of this amount on gasoline for the drive and motel rooms along the way and
1/2
of the remainder on meals. How much does Molly's family plan to spend on meals?

A.
$600

B.
$900

C.
$1,200

D.
$1,500

5 answers

To determine how much Molly's family plans to spend on meals, we can break down the problem step by step.

  1. Calculate the amount spent on gasoline and motel rooms: \[ \text{Amount for gasoline and motel} = \frac{3}{5} \times 3000 = 1800 \]

  2. Calculate the remainder after gas and motel expenses: \[ \text{Remainder} = 3000 - 1800 = 1200 \]

  3. Calculate the amount spent on meals: \[ \text{Amount for meals} = \frac{1}{2} \times 1200 = 600 \]

Therefore, Molly's family plans to spend $600 on meals.

The answer is A. $600.

What is the result of this calculation?

1/2 x 4/3 + 5/6 / 7/8 =




A.
1 27/48

B.
1 13/21

C.
1 33/42

D.
1 19/48

To solve the expression \( \frac{1}{2} \times \frac{4}{3} + \frac{5}{6} \div \frac{7}{8} \), we will follow the order of operations.

  1. Calculate \( \frac{1}{2} \times \frac{4}{3} \): \[ \frac{1}{2} \times \frac{4}{3} = \frac{1 \cdot 4}{2 \cdot 3} = \frac{4}{6} = \frac{2}{3} \quad (\text{simplified}) \]

  2. Calculate \( \frac{5}{6} \div \frac{7}{8} \): To divide by a fraction, we multiply by its reciprocal: \[ \frac{5}{6} \div \frac{7}{8} = \frac{5}{6} \times \frac{8}{7} = \frac{5 \cdot 8}{6 \cdot 7} = \frac{40}{42} = \frac{20}{21} \quad (\text{simplified}) \]

  3. Add the two results together: Now we have: \[ \frac{2}{3} + \frac{20}{21} \] We need a common denominator to add these fractions. The least common multiple of 3 and 21 is 21.

    Convert \( \frac{2}{3} \) to have a denominator of 21: \[ \frac{2}{3} = \frac{2 \cdot 7}{3 \cdot 7} = \frac{14}{21} \]

    Now add the two fractions: \[ \frac{14}{21} + \frac{20}{21} = \frac{14 + 20}{21} = \frac{34}{21} \]

  4. Convert \( \frac{34}{21} \) to a mixed number: \[ 34 \div 21 = 1 \quad \text{remainder } 13 \] So, \( \frac{34}{21} = 1 \frac{13}{21} \).

Therefore, the result of the calculation is:

B. \( 1 \frac{13}{21} \).

Multiple Choice Question
Rashad purchased movie tickets for himself and two friends. After buying the tickets, he has $17 left over to buy snacks for the movie. Snack prices (including tax) are shown below:

Candy $1.50
Popcorn $4.00
Drink $2.75

Which of the following combinations of snacks could Rashad purchase?
A.
2 drinks and 3 popcorns

B.
3 popcorns and 3 candies

C.
4 popcorns and 1 candy

D.
4 drinks and 2 popcorns

To determine which combination of snacks Rashad could purchase with his remaining $17, we can evaluate each option by calculating the total cost of the snacks in each combination.

Snack Prices:

  • Candy: $1.50
  • Popcorn: $4.00
  • Drink: $2.75

A. 2 drinks and 3 popcorns

  • Cost = \( 2 \times 2.75 + 3 \times 4.00 \)
  • Cost = \( 5.50 + 12.00 = 17.50 \)

B. 3 popcorns and 3 candies

  • Cost = \( 3 \times 4.00 + 3 \times 1.50 \)
  • Cost = \( 12.00 + 4.50 = 16.50 \)

C. 4 popcorns and 1 candy

  • Cost = \( 4 \times 4.00 + 1 \times 1.50 \)
  • Cost = \( 16.00 + 1.50 = 17.50 \)

D. 4 drinks and 2 popcorns

  • Cost = \( 4 \times 2.75 + 2 \times 4.00 \)
  • Cost = \( 11.00 + 8.00 = 19.00 \)

Summary of Costs:

  • A: $17.50
  • B: $16.50
  • C: $17.50
  • D: $19.00

The combinations that Rashad could afford (costing $17 or less) are:

  • B. 3 popcorns and 3 candies ($16.50)

The other combinations (A and C) exceed Rashad's budget of $17, while D exceeds it as well.

Therefore, the correct answer is B. 3 popcorns and 3 candies.