P = R + 3
E = 2 R
R + E = 81 ... R + 2 R = 81 ... R = ?
substitute back to find E and P
Ms. Pacheco, Mr. Edwards, and Mr. Richards are three math teachers at Turner Middle School. Ms. Pacheco is three years older than Mr. Richards. Mr. Edwards is twice as old as Mr. Richards. The sum of Mr. Richards’ age and Mr. Edwards’ age is 81. How old is each person?
5 answers
23
Ms. Pacheco is 29, Mr. Richards is 26 and Mr. Edwards is 52.
P = R + 3E = 2 R
R + E = 81
R+
R + E = 81
R+
Ms. Pacheco= R+3 Mr. Edwards = 2 (R) Mr. Richards = ??
Let R= Mr. Richards age
R+ 2 (R)= 81 (The total of Mr. Edwards & Mr. Richards)
R+R+R= 81 3R = 81 (divide both sides to 3)
It would look like: R = 27
The age of Ms. Pacheco is 30 (27+3= 30),
Mr. Edward's age is 54 (2 x 27= 54),
and Mr. Richards is 27.
Btw I have this problem for homework, but it's pretty easy :)
Let R= Mr. Richards age
R+ 2 (R)= 81 (The total of Mr. Edwards & Mr. Richards)
R+R+R= 81 3R = 81 (divide both sides to 3)
It would look like: R = 27
The age of Ms. Pacheco is 30 (27+3= 30),
Mr. Edward's age is 54 (2 x 27= 54),
and Mr. Richards is 27.
Btw I have this problem for homework, but it's pretty easy :)