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Mrs. Nord and Mrs. Schulz went on a school field trip and estimated that 40 students would be there. There were 32 students that attended.

What was their percent error?



(1 point)
Responses

25%
25%

8%
8%

80%
80%

1.25%
1.25%

There were 420 gumballs in a jar but then more were added so that there were 500 gumballs. What is the percent of change? Round to the nearest whole percent.

(1 point)
Responses

80%
80%

16%
16%

84%
84%

19%

A fitness watch was on sale for $119.99. It was originally priced $179.99. What is the percent of change? Round to the nearest whole percent.

(1 point)
Responses

60%
60%

67%
67%

33%
33%

50%

1 answer

Let's calculate each scenario one by one:

  1. Percent Error for Mrs. Nord and Mrs. Schulz's Estimate:

    • Estimated Value: 40 students
    • Actual Value: 32 students
    • Percent Error formula: \[ \text{Percent Error} = \left( \frac{|\text{Estimated Value} - \text{Actual Value}|}{\text{Estimated Value}} \right) \times 100 \]
    • Plugging in the values: \[ \text{Percent Error} = \left( \frac{|40 - 32|}{40} \right) \times 100 = \left( \frac{8}{40} \right) \times 100 = 20% \]
    • So, the correct answer is not among the responses. However, if looking for the closest answer, they estimated high, leading to an error of 20%.

  2. Percent of Change for Gumballs:

    • Initial Value: 420 gumballs
    • New Value: 500 gumballs
    • Percent Change formula: \[ \text{Percent Change} = \left( \frac{\text{New Value} - \text{Initial Value}}{\text{Initial Value}} \right) \times 100 \]
    • Plugging in the values: \[ \text{Percent Change} = \left( \frac{500 - 420}{420} \right) \times 100 = \left( \frac{80}{420} \right) \times 100 \approx 19.05% \]
    • Rounding to the nearest whole percent, the answer is 19%.

  3. Percent of Change for the Fitness Watch:

    • Original Price: $179.99
    • Sale Price: $119.99
    • Percent Change formula: \[ \text{Percent Change} = \left( \frac{\text{Original Price} - \text{Sale Price}}{\text{Original Price}} \right) \times 100 \]
    • Plugging in the values: \[ \text{Percent Change} = \left( \frac{179.99 - 119.99}{179.99} \right) \times 100 = \left( \frac{60}{179.99} \right) \times 100 \approx 33.34% \]
    • Rounding to the nearest whole percent, the answer is 33%.

Summary of Answers:

  1. Percent Error for students: 20% (not among given responses).
  2. Percent Change for gumballs: 19%.
  3. Percent Change for fitness watch: 33%.