To solve this problem, we can use a system of equations based on the information given.
Let's denote:
- \( x \) = the amount of the 4% liquid (in ounces)
- \( y \) = the amount of the 20% liquid (in ounces)
From the problem, we know that:
-
The total volume of the mixture is 6 ounces: \[ x + y = 6 \]
-
The total amount of reactor fuel in the final mixture should equal 8% of 6 ounces: \[ 0.04x + 0.20y = 0.08 \times 6 \] Simplifying the right side gives: \[ 0.04x + 0.20y = 0.48 \]
Now we have a system of equations:
- \( x + y = 6 \)
- \( 0.04x + 0.20y = 0.48 \)
We can solve for \( y \) from the first equation: \[ y = 6 - x \]
Substituting \( y \) into the second equation gives: \[ 0.04x + 0.20(6 - x) = 0.48 \] Expanding this: \[ 0.04x + 1.2 - 0.20x = 0.48 \] Combining like terms: \[ -0.16x + 1.2 = 0.48 \] Now, isolate \( x \): \[ -0.16x = 0.48 - 1.2 \] \[ -0.16x = -0.72 \] Dividing both sides by -0.16: \[ x = \frac{-0.72}{-0.16} = 4.5 \]
Now that we have \( x \), we can find \( y \): \[ y = 6 - x = 6 - 4.5 = 1.5 \]
Thus, the amount of the 4% liquid that Mrs. Gargantua must use is: \[ \boxed{4.5 \text{ ounces}} \]