Question

Mrs. Franks is taking her kindergarten class to the circus. She spent a total of $180 for 20 child tickets. If a child ticket is $5 less than an adult ticket, determine the price of an adult and child ticket. Represent this situation with an equation using m as the cost of the adult ticket.(1 point) Drop target 1 Drop target 2 Drop target 3

Answer 1

Given that the cost of a child ticket is $5 less than the cost of an adult ticket, we can represent the cost of the adult ticket as \( m \). Therefore, the cost of a child ticket can be represented as \( m - 5 \).

Since Mrs. Franks bought 20 child tickets for a total of $180, we can set up the following equation to represent the total cost:

\[
20(m - 5) = 180
\]

This equation can be solved to find the price of both child and adult tickets.

### Step 1: Simplify the equation
Distribute the 20 on the left side:

\[
20m - 100 = 180
\]

### Step 2: Add 100 to both sides
\[
20m = 280
\]

### Step 3: Divide by 20
\[
m = 14
\]

### Step 4: Find the cost of a child ticket
The cost of a child ticket is:

\[
m - 5 = 14 - 5 = 9
\]

### Final Prices
- Adult ticket price: $14
- Child ticket price: $9

So, the prices are:

- **Adult ticket (m)**: $14
- **Child ticket (m - 5)**: $9