Mrs. Amrhein made a cylindrical can. It has a height of 5 in and a diameter of 3 in. How much material does she need to wrap the can with no over lap?

Question

TOTAL Surface Area
Mrs. Amrhein made a cylindrical can. It has a height of 5 in and a diameter of 3 in. How much material does she need to wrap the can with no over lap?

TOTAL Surface Area

Answer 1

To find the total surface area of the cylindrical can, we need to calculate the lateral surface area and the area of the two circular bases.

The lateral surface area of a cylinder is given by the formula: 2πrh, where r is the radius and h is the height. Since the diameter is 3 in, the radius (r) is half of that, which is 1.5 in.

So, the lateral surface area = 2π(1.5)(5) = 15π in^2.

The area of one circular base is given by the formula: πr^2.

So, the total area of the two circular bases = 2(π(1.5)^2) = 4.5π in^2.

Therefore, the total surface area of the cylindrical can = 15π + 4.5π = 19.5π in^2.

Approximately, the total surface area is 61.3 in^2.

Mrs. Amrhein needs approximately 61.3 square inches of material to wrap the can with no overlap.