mr. slott at his fighting weight of 1000N jumps down from a platform meters above a trampoline with a spring constant (k) of 500N/M. How much does Mr.Slott strech the trampoline (x) before it brings him to a stop
2 answers
d = 1000N * 1m/500N = 2 m.
A/c to definition of weight
F=W
A/c to hooke's law:
F=kx
Now, if F=W then;
W=kx
1000=500. x
X=1000รท500
X=2m
F=W
A/c to hooke's law:
F=kx
Now, if F=W then;
W=kx
1000=500. x
X=1000รท500
X=2m