don't be put off by all the words. Just write each fact down as math.
You have several amounts: a,b,c,e,g.
2a = 3c = 4e
5b = 6e = 8g
Since the LCM(2,3,4) = 12,
2a,3c,4e must be a multiple of 12
Since LCM(5,6,8) = 120,
5b,6e,8g must be a multiple of 120
Now, if 4e is a multiple of 12, e >= 3. if 6e is a multiple of 120, we must have e >= 20.
So, e must be 60. Given that, 4e=240 and 6e=360
2a = 3c = 4e = 240, so
a=120 and c=80
5b = 6e = 8g = 360, so
b=72 and g=45
a+b+c+e+g = 377
Mr ram has five sons ajay,balu,charan,easwar and ganesh. He had some chocolates with him which he distributed in the following manner. Twice the number of chocolates received by ajay, thrice the number of chocolates received by charan and four times the number of chocolates received by easwar are equal. Five times the number of chocolates received by balu, six times the number of chocolates received by easwar and 8 times the number of chocolates received by ganesh are equal. find the minimum number of chocolates that could have been distributed by Mr.Ram
Please help me solve this.
1 answer
1 answer