Nope. How at that rate, he ate the 125 hotdogs in less than three days.
Day 1: 55
Day 2: 55 + 7 = 62
55 + 62 = 112
"Mr. Macho, my great dane, ate 125 hotdogs over a five-day period. Each day he atee seven more hot dogs than on the previous day. How many hot dogs did he eat on the first day?"
I got 55 hot dogs. Is this right??
6 answers
well I thought tnis was right because the question stated that he ate 7 more than the previous day..
For example day 2 55+7 + 62
Day 3: 62 + 14 = 76 (7 more than day 2)
Day 4: 76 + 21 = 97 (7 more than day 3)
Day 5: 97 + 28 = 125(7more than day 4)
For example day 2 55+7 + 62
Day 3: 62 + 14 = 76 (7 more than day 2)
Day 4: 76 + 21 = 97 (7 more than day 3)
Day 5: 97 + 28 = 125(7more than day 4)
I see what you're thinking, but I believe you're wrong.
Each day he ate seven more hot dogs than on the previous day.
It seems to me the dog ate between 10 and 15 hotdogs the first day.
Each day he ate seven more hot dogs than on the previous day.
It seems to me the dog ate between 10 and 15 hotdogs the first day.
first day: x hotdogs
second day: x+7
third: x+14
fourth: x+21
fifth : x+28
x + x+7 + x+14 + x+21 + x+28 = 125
5x + 70 = 125
5x = 55
x = 11
so he ate 11, 18, 25, 32, 39
addd them up, it totals 125
second day: x+7
third: x+14
fourth: x+21
fifth : x+28
x + x+7 + x+14 + x+21 + x+28 = 125
5x + 70 = 125
5x = 55
x = 11
so he ate 11, 18, 25, 32, 39
addd them up, it totals 125
Thanks for everybodys help, I understand the math now.
i have th exact same problem!