Mr.kamau sold two thirds of his fruits on Monday and ¾ of the remainder on Tuesdays he had then 60 left.how many fruits had she at first

Answer 1

Let's assume Mr. Kamau had x fruits at first.

On Monday, he sold 2/3 of his fruits, leaving 1/3 of the fruits.
1/3 of x = x/3 fruits remaining

On Tuesday, he sold 3/4 of the remaining fruits, leaving 1/4 of the fruits.
1/4 of x/3 = x/12 fruits remaining

According to the given information, he had 60 fruits left after Tuesday.
So, x/12 = 60
x = 60 * 12
x = 720

Therefore, Mr. Kamau had 720 fruits at first.