mr hibbard found a magic penny which doubles in value every day the expression .01 • 2^x where x is the number days since mr hibbard found the penny

mr hibbard realized after just 2 weeks the penny had becomr $163.84 how did he reach this solution

1 answer

To understand how Mr. Hibbard reached the value of $163.84 after 2 weeks with the magic penny that doubles in value every day, we can break it down mathematically using the expression \(0.01 \times 2^x\), where \(x\) is the number of days since he found the penny.

Step-by-step Calculation:

  1. Determine the Number of Days:
    Mr. Hibbard realized after just 2 weeks. Since there are 14 days in 2 weeks, we set \(x = 14\).

  2. Substitute \(x\) into the Expression:
    Using the expression \(0.01 \times 2^x\), we substitute \(x\) with 14: \[ \text{Value after 14 days} = 0.01 \times 2^{14} \]

  3. Calculate \(2^{14}\):
    First, we need to compute \(2^{14}\):

    • \(2^{10} = 1024\)
    • Therefore, \(2^{14} = 2^{10} \times 2^4 = 1024 \times 16 = 16384\).
  4. Multiply by 0.01:
    Now, we multiply this result by \(0.01\): \[ 0.01 \times 16384 = 163.84 \]

Conclusion:

So, after 14 days, the penny had indeed become $163.84. Mr. Hibbard used the expression correctly to reach this solution:

\[ \text{Value} = 0.01 \times 2^{14} = 163.84 \]