To determine the specific heat of each liquid sample, we can use the formula:
\[ q = mc\Delta T \]
where:
- \( q \) = heat energy (which is constant for all samples since they were heated in the same way)
- \( m \) = mass of the liquid (given as 200 grams for all samples)
- \( c \) = specific heat of the liquid
- \( \Delta T \) = change in temperature
First, we need to calculate the temperature change (\( \Delta T \)) for each sample:
-
Sample 1:
- Start Temperature = 23°C
- End Temperature = 69°C
- \( \Delta T = 69°C - 23°C = 46°C \)
-
Sample 2:
- Start Temperature = 20°C
- End Temperature = 67°C
- \( \Delta T = 67°C - 20°C = 47°C \)
-
Sample 3:
- Start Temperature = 21°C
- End Temperature = 65°C
- \( \Delta T = 65°C - 21°C = 44°C \)
-
Sample 4:
- Start Temperature = 22°C
- End Temperature = 70°C
- \( \Delta T = 70°C - 22°C = 48°C \)
Now we have the temperature changes for each sample:
- Sample 1: \( \Delta T = 46°C \)
- Sample 2: \( \Delta T = 47°C \)
- Sample 3: \( \Delta T = 44°C \)
- Sample 4: \( \Delta T = 48°C \)
Since \( q \) is the same for all samples and the mass \( m \) is the same, the specific heat \( c \) can be determined by the temperature change. The specific heat is inversely proportional to the temperature change; the larger the temperature change, the lower the specific heat.
Now, we can order the samples by their temperature change from lowest to highest:
- Sample 3: \( \Delta T = 44°C \) (highest specific heat)
- Sample 1: \( \Delta T = 46°C \)
- Sample 2: \( \Delta T = 47°C \)
- Sample 4: \( \Delta T = 48°C \) (lowest specific heat)
Thus, the order of the unknown liquid samples by specific heat from lowest to highest is:
Sample 4 < Sample 2 < Sample 1 < Sample 3.