Mr. Gonzalez asks his top three students to find a factor of x^4-3x^3-19x^2+3x+18 given that

x-1 is one of the linear factors. Which of the students is correct?
Student #1: x^2+9x+18
Student #2: x^3-2x^2-21x-18
Student #3: x^3-2x^2-21x+18



A
Student #1

B
Student #2

C
Student #3

D
None of the students

1 answer

To find out which of the students is correct, we can use polynomial long division to divide the polynomial \( x^4 - 3x^3 - 19x^2 + 3x + 18 \) by the factor \( x - 1 \).

  1. Perform the Polynomial Long Division:
    • Divide the leading term \( x^4 \) by \( x \), which gives \( x^3 \).

    • Multiply \( x^3 \) by \( x - 1 \) to get \( x^4 - x^3 \).

    • Subtract \( x^4 - x^3 \) from \( x^4 - 3x^3 - 19x^2 + 3x + 18 \) to get: \[ (-3x^3 + x^3) - 19x^2 + 3x + 18 = -2x^3 - 19x^2 + 3x + 18 \]

    • Divide the leading term \( -2x^3 \) by \( x \), which gives \( -2x^2 \).

    • Multiply \( -2x^2 \) by \( x - 1 \) to get \( -2x^3 + 2x^2 \).

    • Subtract \( -2x^3 + 2x^2 \) from the previous polynomial: \[ (-2x^3 + 2x^2) - 19x^2 + 3x + 18 = -21x^2 + 3x + 18 \]

    • Divide the leading term \( -21x^2 \) by \( x \), which gives \( -21x \).

    • Multiply \( -21x \) by \( x - 1 \) to get \( -21x^2 + 21x \).

    • Subtract \( -21x^2 + 21x \) from the previous polynomial: \[ (-21x^2 + 21x) + 3x + 18 = -18x + 18 \]

    • Finally, divide the leading term \( -18x \) by \( x \), which gives \( -18 \).

    • Multiply \( -18 \) by \( x - 1 \) to get \( -18x + 18 \).

    • Subtract \( -18x + 18 \) from the previous polynomial: \[ (-18x + 18) - (-18x + 18) = 0 \]

This gives us the result of the division: \[ x^4 - 3x^3 - 19x^2 + 3x + 18 = (x - 1)(x^3 - 2x^2 - 21x - 18). \]

  1. Identify the Correct Student:
    • From the polynomial division, we can see that the other factor is \( x^3 - 2x^2 - 21x - 18 \).
    • This matches the answer given by Student #2.

Therefore, the correct answer is:

B - Student #2