Mr. Digit wanted to assign a number to each student in his class. He could only use the digits 2,3,and 6 and each student's number had to have three digits. Can he find enough numbers for all 25 students if repeated digits are allowed? Will there be any extra numbers?

Answer 1

There may be a shortcut to finding this answer -- but you can do it this way:

222
223
226
232
233
236
262
263
266
Do the same with numbers beginning with 3 and 6.

Answer 2

Or you could just count how many numbers Ms. Sue provided and multiply by three for your total number of possiblities.