Mr. Bert deposited $5,000 into an investment account 20 years ago with an annual interest rate of 3.75%. a) Find the exponential function in the form f(x)=a⋅bx to represent the total value of Mr. Bert’s investment account over time. b) Mr. Bert will retire in 15 years. What will be the total value of his investment when he retires? What is the percent increase of this final amount compared to the initial amount of the investment? Round the answers to two decimal places. (4 points)

1 answer

To solve this problem, we can follow these steps:

Part a: Find the Exponential Function

The formula for the future value of an investment compounded annually is given by:

\[ f(t) = P(1 + r)^t \]

where:

  • \( P \) is the principal amount (initial investment),
  • \( r \) is the annual interest rate (as a decimal),
  • \( t \) is the time in years.

Given:

  • \( P = 5000 \),
  • \( r = 3.75% = \frac{3.75}{100} = 0.0375 \),
  • We denote \( t \) as the number of years since the initial deposit.

Thus, the function can be written as:

\[ f(t) = 5000(1 + 0.0375)^t \]

To express it in the form \( f(x) = a \cdot b^x \):

Here, \( a = 5000 \) and \( b = 1 + 0.0375 = 1.0375 \).

So the exponential function is:

\[ f(t) = 5000(1.0375)^t \]

Part b: Calculate the Total Value When Mr. Bert Retires

Mr. Bert will retire in 15 years; since the investment account was made 20 years ago, we find the total number of years from the initial deposit until retirement:

\[ \text{Total time until retirement} = 20 + 15 = 35 \text{ years} \]

Now, we can substitute \( t = 35 \) into the exponential function:

\[ f(35) = 5000(1.0375)^{35} \]

Now let's calculate \( (1.0375)^{35} \):

\[ (1.0375)^{35} \approx 3.578217 \]

Now substitute back into the function:

\[ f(35) = 5000 \cdot 3.578217 \approx 17891.09 \]

So, the total value of the investment when Mr. Bert retires is approximately:

\[ \text{Total Value} \approx 17891.09 \]

Percent Increase Calculation

To find the percent increase compared to the initial amount, we use the formula for percentage increase:

\[ \text{Percent Increase} = \frac{\text{Final Amount} - \text{Initial Amount}}{\text{Initial Amount}} \times 100 \]

Substituting the values:

\[ \text{Percent Increase} = \frac{17891.09 - 5000}{5000} \times 100 = \frac{12891.09}{5000} \times 100 \approx 257.82% \]

Final Answers:

  • a) The exponential function is \( f(t) = 5000(1.0375)^t \).
  • b) Total value at retirement is approximately $17,891.09 and the percent increase is 257.82%.