Note that (c^2+2cd+d^2) = (c+d)^2
That means the area is (c+d)^2 * (c+d) = (c^2)^3
Now, divide the total area by the area covered by one can to get the number of cans needed.
Mr.Aquino wants to paint the ceiling of a room that has length of (c^2+2cd+d^2) meters and width of (c+d) meters. If one can of paint will cover (c+d)^2 square meter, what is the minimum number of cans of paint needed? Express your answer as a polynomials.
3 answers
I hope you caught my top. The total area is (c+d)^3
thanks a lot, because you help many people on how to solve that questions.