Question

Mr.Aquino wants to paint the ceiling of a room that has length of (c^2+2cd+d^2) meters and width of (c+d) meters. If one can of paint will cover (c+d)^2 square meter, what is the minimum number of cans of paint needed? Express your answer as a polynomials.

Answer 1

Note that (c^2+2cd+d^2) = (c+d)^2

That means the area is (c+d)^2 * (c+d) = (c^2)^3

Now, divide the <u>total area</u> by the <u>area covered by one can</u> to get the <u>number of cans</u> needed.

Answer 2

I hope you caught my top. The total area is (c+d)^3

Answer 3

thanks a lot, because you help many people on how to solve that questions.