Asked by physics
Monochromatic light from a helium-neon laser (wavelength=632.8 nm) shines at a right angle onto the surface of a diffraction grating that contains 130 960 lines/m. Find the angle at which one would observe the first-order maximum.
formula: (a+b)Sin theta = n wavelength
(a+b) = 1
____ m; n=1
wavelength=632.8*10^-9 m
=6.328*10^-7m
Sin theta=6.32^8 * 10^-7 * 130960
= 6.328*10^-7*130960*10^5
theta= 4.7536deg
= 4.75
is this done correctly?
130960
formula: (a+b)Sin theta = n wavelength
(a+b) = 1
____ m; n=1
wavelength=632.8*10^-9 m
=6.328*10^-7m
Sin theta=6.32^8 * 10^-7 * 130960
= 6.328*10^-7*130960*10^5
theta= 4.7536deg
= 4.75
is this done correctly?
130960
Answers
Answered by
drwls
I don't know what a and b are supposed to be in your diffrection grating formula. The correct form of the quation is
d (sin i + sinr) = m*lambda
where i and r are the angles of incidence and reflection.
In your case sin i = 0, m = 1, and d is the grating line separation, which is your case is 1/(130960m^-1) = 7.636*10^-6 m.
Therefore
d sin r = 632.8*10^-9 m
sin r = 632.8*10^-9*130960 = 0.08287
r = 4.75 degrees
So you got the right answer, anyway
d (sin i + sinr) = m*lambda
where i and r are the angles of incidence and reflection.
In your case sin i = 0, m = 1, and d is the grating line separation, which is your case is 1/(130960m^-1) = 7.636*10^-6 m.
Therefore
d sin r = 632.8*10^-9 m
sin r = 632.8*10^-9*130960 = 0.08287
r = 4.75 degrees
So you got the right answer, anyway
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.