Without knowing the total mass of the solution, we can only calculate the relative masses of HNO3 and H2O.
Let's assume there are 1000 g of the solution. Then, the mole fraction of HNO3 is:
Mole fraction of HNO3 = moles of HNO3 / total moles
0.175 = moles of HNO3 / (moles of HNO3 + moles of H2O)
We can rearrange this equation to solve for moles of H2O:
moles of H2O = moles of HNO3 / 0.175 - moles of HNO3
moles of H2O = moles of HNO3 / 0.825
Now, we need to know the molar mass of HNO3 and H2O. HNO3 has a molar mass of 63 g/mol and H2O has a molar mass of 18 g/mol.
The total moles of the solution is:
moles of solution = 1000 g / (63 g/mol x 0.175 + 18 g/mol x moles of H2O)
We can solve for moles of H2O using the equation we derived above and substitute it into the equation for moles of solution:
moles of solution = 1000 g / (63 g/mol x 0.175 + 18 g/mol x (moles of HNO3 / 0.825))
moles of solution = 12.085
Now, we can calculate the mass of HNO3 and H2O:
mass of HNO3 = moles of HNO3 x molar mass of HNO3
mass of HNO3 = 0.175 x 12.085 x 63 g/mol
mass of HNO3 = 133.8 g
mass of H2O = moles of H2O x molar mass of H2O
mass of H2O = (moles of HNO3 / 0.825) x 18 g/mol
mass of H2O = 862.7 g
Therefore, in a 1000 g solution with a mole fraction of HNO3 of 0.175, there are approximately 133.8 g of HNO3 and 862.7 g of H2O.
mole fraction of HNO3 is 0.175. calculate mass of nitric acid and H2O.
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