Molarity of CH3CO2H when there are 0.0019536 moles of CH3CO2H and the volume of NaOH tires red was 16.28 mL

Answer 1

To determine the molarity of CH3CO2H, we need to use the equation:

Molarity (M) = moles of solute / volume of solution in liters

Given:
moles of CH3CO2H = 0.0019536 moles
volume of NaOH titrated = 16.28 mL = 0.01628 L

Now, substitute the values into the equation:

Molarity (M) = 0.0019536 moles / 0.01628 L

Calculating this gives:
Molarity (M) ≈ 0.120 M

Therefore, the molarity of CH3CO2H is approximately 0.120 M.