Mohammedwalks 3km from pointA on a bearingof023 he thenwalks 4km on a bearing of 113 to a point B what is the bearing of B from A

Answer 1

you walk on a heading, not a bearing.
If A is at (0,0) then his first turn is at
X is at A+(3sin23° , 3cos23°) = (1.172,2.761)
and B is at X + (4cos23° , -4sin23°) = (4.854,1.198)
so the bearing of B from A is θ, where tanθ = 4.854/1.198 ≈ 76°