To calculate the partial pressure of each gas, we first need to find the moles of each gas by using the ideal gas law equation:
PV = nRT
Where:
P = pressure of the gas
V = volume of the gas
n = number of moles of the gas
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature in Kelvin
For helium:
P(He) = n(He) * R * T / V
P(He) = (46L * 1 atm) * 0.0821 L.atm/mol.K * (25 + 273) K / 5.0 L
P(He) = 48.418 atm
For oxygen:
P(O2) = n(O2) * R * T / V
P(O2) = (12L * 1 atm) * 0.0821 L.atm/mol.K * (25 + 273) K / 5.0 L
P(O2) = 12.105 atm
To find the total pressure in the tank, simply add the partial pressures of both gases:
Total pressure = P(He) + P(O2)
Total pressure = 48.418 atm + 12.105 atm
Total pressure = 60.523 atm
Therefore, the partial pressure of helium is 48.418 atm, the partial pressure of oxygen is 12.105 atm, and the total pressure in the tank is 60.523 atm.
Mixture of helium and oxygen can be used in scuba diving tanks to help prevent the bends , for a particulr dive 46L of He and 12L of O2 both at 25 degrees Celsius and 1.0 atm were pumped into a tank with a volume of 5.0L . Calculate the partial pressure of each gas and the total pressure in the tank at 25 degrees Celsius
1 answer
1 answer