Misha writes the following proof that two distinct lines, l

Question

and n
, with the same slope, m
, are parallel. She uses a proof by contradiction. Which step did she do incorrectly?

Assume that distinct lines l
and n
have the same slope, m
, but are not parallel.
Let l
have the equation y=mx+b
and n
have the equation y=mx+c
. In order to be distinct lines, it must be true that b≠c
.
Since they are assumed to not be parallel, they must have a point of intersection.
Set the equations for l
and n
equal to each other and solve to find the x
-coordinate of the point of intersection.
Setting mx+b
equal to mx+c
results in b=c
, which contradicts the condition that b≠c
.
Therefore the assumption that two distinct lines with the same slope are not parallel is incorrect. It must be true that two distinct lines with the same slope are parallel.
(1 point)
Responses

Step 3 is incorrect. The lines do not need to have a point of intersection since they are not parallel.
Step 3 is incorrect. The lines do not need to have a point of intersection since they are not parallel.

Step 5 is incorrect. Both equations need to be solved for x
first, then set equal to each other in order to directly solve for the x
-intercept.
Step 5 is incorrect. Both equations need to be solved for x first, then set equal to each other in order to directly solve for the x-intercept.

Answer 1

The incorrect step in Misha's proof is:

Step 3 is incorrect. The lines do not need to have a point of intersection since they are not parallel.

Misha assumes that if the lines are not parallel, then they must intersect, which is only true for distinct lines that are not parallel. However, if two lines are distinct and have the same slope, they are inherently parallel and do not intersect at any point. Since the proof relies on them having a point of intersection to reach a contradiction, this assumption is flawed. Therefore, the reasoning falls apart, making the step incorrect.