The error in Misha's proof lies in the assumption that distinct lines \(l\) and \(n\) with the same slope \(m\) can intersect. The key fact to recognize is that if two distinct lines have the same slope, they must be parallel.
Here's the flaw in reasoning in more detail:
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Misha starts with the equations \(y = mx + b\) (for line \(l\)) and \(y = mx + c\) (for line \(n\)), where \(b \neq c\) ensures the lines are distinct.
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She states that since the lines are distinct, they must intersect at a point. However, this statement is where the assumption begins to fail. If line \(l\) and line \(n\) have the same slope, they will never intersect because parallel lines do not meet.
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Consequently, when she sets \(mx + b = mx + c\) and derives \(b = c\), she is arriving at a contradiction based on incorrect premises. The contradiction arises not because her calculations are wrong, but because the initial assumption that two distinct lines with the same slope can intersect is false.
Therefore, Misha's mistake is in the assumption that distinct lines with the same slope can intersect. This is incorrect because parallel lines, by definition, do not intersect. Thus, she should conclude that if the lines are distinct and have the same slope, they must be parallel.