Minimize S=x+2y with xy=2 and both x and y > 0
Put F(x,y) = xy
Then we have:
dS/dx = lambda dF/dx (1)
dS/dy = lambda dF/dy (2)
Eq. (1) gives:
lambda y = 1 (3)
Eq. (2) gives:
lambda x = 2 (4)
If you divide (4) by (3 you get:
x/y = 2 (5)
We also know that
xy=2 (6)
If you multiply (5) by (6) you get x^2 = 4 which yields x = 2 because we knbow that x has to be positive. And this implies that y = 1
Minimize S=x+2y with xy=2 and both x and y > 0
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