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Sure! Let's go through examples of both addition and subtraction using scientific notation.
Example 1: Addition
Problem: \( 2.5 \times 10^3 + 3.1 \times 10^2 \)
Step 1: Adjust to the same power of 10.
To add these two numbers, we should express them with the same exponent. The second number, \( 3.1 \times 10^2 \), can be rewritten as:
\[ 3.1 \times 10^2 = 0.31 \times 10^3 \]
Step 2: Now, add the coefficients.
Now we can add them:
\[ 2.5 \times 10^3 + 0.31 \times 10^3 = (2.5 + 0.31) \times 10^3 = 2.81 \times 10^3 \]
Result:
\[ 2.5 \times 10^3 + 3.1 \times 10^2 = 2.81 \times 10^3 \]
Example 2: Subtraction
Problem: \( 5.4 \times 10^4 - 2.1 \times 10^3 \)
Step 1: Adjust to the same power of 10.
We can convert \( 2.1 \times 10^3 \) to have the same exponent as \( 5.4 \times 10^4 \):
\[ 2.1 \times 10^3 = 0.21 \times 10^4 \]
Step 2: Now, subtract the coefficients.
Now we perform the subtraction:
\[ 5.4 \times 10^4 - 0.21 \times 10^4 = (5.4 - 0.21) \times 10^4 = 5.19 \times 10^4 \]
Result:
\[ 5.4 \times 10^4 - 2.1 \times 10^3 = 5.19 \times 10^4 \]
If you have any further questions or need clarification, feel free to ask!
Absolutely! Let’s go through the addition and subtraction with scientific notation in a more conversational style.
Example 1: Addition
Problem: What’s \( 2.5 \times 10^3 + 3.1 \times 10^2 \)?
-
First, let's align the terms.
We see that \( 2.5 \times 10^3 \) is in the thousands, but \( 3.1 \times 10^2 \) is only in the hundreds. To make it easier to add, we can convert \( 3.1 \times 10^2 \) into the same power of ten as the first term.
So, we rewrite \( 3.1 \times 10^2 \) as \( 0.31 \times 10^3 \). -
Now, let’s add.
With both terms now in terms of \( 10^3 \), we can add the coefficients:
\[ 2.5 + 0.31 = 2.81 \] -
Putting it together, we have:
\[ 2.5 \times 10^3 + 3.1 \times 10^2 = 2.81 \times 10^3 \]
Example 2: Subtraction
Problem: How about \( 5.4 \times 10^4 - 2.1 \times 10^3 \)?
-
Align the terms again.
Here, \( 5.4 \times 10^4 \) is in the tens of thousands, while \( 2.1 \times 10^3 \) is only in the thousands. So, let’s convert \( 2.1 \times 10^3 \) to match the power of ten of the first number:
We can rewrite it as \( 0.21 \times 10^4 \). -
Now, it’s time to subtract.
With both terms in terms of \( 10^4 \), we can perform the subtraction:
\[ 5.4 - 0.21 = 5.19 \] -
So, our final answer is:
\[ 5.4 \times 10^4 - 2.1 \times 10^3 = 5.19 \times 10^4 \]
Summary
- For addition: \( 2.5 \times 10^3 + 3.1 \times 10^2 = 2.81 \times 10^3 \)
- For subtraction: \( 5.4 \times 10^4 - 2.1 \times 10^3 = 5.19 \times 10^4 \)
I hope this makes it clearer! If you have any more questions or need further explanation, just let me know!
Sure! Here’s a shorter version of the addition and subtraction in scientific notation:
Example 1: Addition
Problem: \( 2.5 \times 10^3 + 3.1 \times 10^2 \)
- Convert: Rewrite \( 3.1 \times 10^2 \) as \( 0.31 \times 10^3 \).
- Add: \[ 2.5 + 0.31 = 2.81 \]
- Result: \[ 2.5 \times 10^3 + 3.1 \times 10^2 = 2.81 \times 10^3 \]
Example 2: Subtraction
Problem: \( 5.4 \times 10^4 - 2.1 \times 10^3 \)
- Convert: Rewrite \( 2.1 \times 10^3 \) as \( 0.21 \times 10^4 \).
- Subtract: \[ 5.4 - 0.21 = 5.19 \]
- Result: \[ 5.4 \times 10^4 - 2.1 \times 10^3 = 5.19 \times 10^4 \]
Let me know if you need anything else!
Got it! Let’s do an example of addition and subtraction using numbers already in scientific notation.
Example 1: Addition in Scientific Notation
Problem: \( (3.0 \times 10^4) + (4.5 \times 10^4) \)
-
Add the coefficients:
\[ 3.0 + 4.5 = 7.5 \] -
Keep the exponent the same:
\[ = 7.5 \times 10^4 \]
Result:
\[
(3.0 \times 10^4) + (4.5 \times 10^4) = 7.5 \times 10^4
\]
Example 2: Subtraction in Scientific Notation
Problem: \( (6.0 \times 10^5) - (2.2 \times 10^5) \)
-
Subtract the coefficients:
\[ 6.0 - 2.2 = 3.8 \] -
Keep the exponent the same:
\[ = 3.8 \times 10^5 \]
Result:
\[
(6.0 \times 10^5) - (2.2 \times 10^5) = 3.8 \times 10^5
\]
Let me know if this is what you were looking for!