Question

Mindy, Jake and Donald shared a sum of money. The amount received by Jake was 2/3 the amount of money received by Donald. After Mindy had given $48 to Jake and $27 to Donald, Jake gave $3 to Donald. In the end, 3 of them had the same amount of money. Find the difference between the amount of money that Mindy and Jake had at first

Answer 1

First write down what they tell you.
j = 2/3 d
m-48-27 = j+48-3 = d+27+3
now just solve that for j,m,d and then you want m-j
Post your work if you get stuck.

Answer 2

First write down what they tell you.
j = 2/3 d
m-48-27 = j+48-3 = d+27+3
now just solve that for j,m,d and then you want m-j
=> m - 75 = j + 45 = d + 30
=> m - 75 = 2/3 d + 45 = d + 30
=> m - 75 = 2/3 d - d = 30 - 45
=> (2/3 - 1) d = 30 - 45
=> ((2-3)/3) d = - 15
=> d * 1/3 = - 15
=> d = - 15/1/3
=> d = - 15 * 3/1
=> d = - 45

=> m - 75 = d = - 45
=> m - 75 = - 45
=> m = - 45 + 75
= 30
J = 2/3 d
=> J = 2/3 * - 45
= - 30
M - J = 30 - 30
= 0
Answer
J = -30
m = 30
d = -45
m - j = 0

Answer 3

Jake = 2/3 of Donald
Mindy = 2 (Jared & Donald) 2 (x + 2/3x)
Mindy = 2 ((3x + 2x)/3) = $10x/3
Mindy gave $48 and $27 to Jake and Donald respectively so Mindy have 10x/3 - $48 - $27
Mindy = 10x/3 - $75
Jake = 2/3x + $48 - $3 = 2/3x + $45
10x/3 - $75 = 2/3x + $45
10x/3 - 2/3x = $45 + $75
8x/3 = $120
Answer $120

Answer 4

First write down what they tell you.
j = 2/3 d
m-48-27 = j+48-3 = d+27+3
now just solve that for j,m,d and then you want m-j

j = 2/3 d
m-48-27 = j+48-3 = d+27+3
j + 48 - 3 = d + 27 + 3
2/3 d + 48 - 3 = d + 27 + 3
45 - 30 = d - 2/3 d
15 * 3 = 3d - 2d
45 = d
j = 2 * 15 = 30
j = 30
m - 48 - 27 = 45 + 27 + 3
m - 75 = 75
m = 75 + 75
m = 150

m - j = 150 - 30 = 120
m - j = 120