If there are x 4-seaters, and y 10-seaters, then
x+y <= 52
4x + 10y >= 280
see the solution set at
http://www.wolframalpha.com/input/?i=solve+x%2By+%3C%3D+52%2C+4x+%2B+10y+%3E%3D+280%2C+x%3E%3D0%2C+y%3E%3D0
Mina's catering service is organizing a formal dinner for 280 people.The hall has two kinds of tables, one that seats 4 people and one that seats 10 people.The hall can contain up to a total of 52 tables.Write and graph a system of inequalities that can be used to determine the possible combinations of tables that can be used for the event so there are enough seats for all people,
1 answer